I chose a fraction half way between 4 and 3 1/2 and ended up with 3 3/4.That seemed to do the trick. To do this I must change the 7/2 ever so slightly. The parabola moved to theleft directly underneath the red graph with which I want it to share a vertex.The only thing left to do is to move the brown up slightly so that theytouch. So I began with the "b"part of the equation. I knew that the "c" part of theequation moved the graph up and down and I knew that the "a" partof the equation "flipped" the parabola. I know I will probably need another negative somewhere,so I will try a few graphs. Next, I need to move the bluegraph to the left. I will probably have to adjust it again later,but this is a good place for me to start. Neither graph waslow enough to be anywhere close to the vertex of the red parabola. I needed itto move down, I changed the (+6) to (+5) and then (+4). I knew that(+6) moved the parabola "up" from where it began. I tried 2 other graphs before I ended up with this blue one. Now I will try to move the green parabola down and to theleft to share the same vertex. I just thought it would flip it at its lowest point,but it didn't. Something from my past told me that if I negated the squared part ofthe problem, that it would "flip" the parabola.
Graphing parts of a 3d graph in graphmatica how to#
I will attempt this by trial and error and then see if I canmake a general statement on how to find the equation with an easier method. My next objectiveis to change the equation to produce a graph concave down that shares thesame vertex. Now I will delete the first3 graphs and just work with the one in the 2nd quadrant. The graph did move into the 2nd quadrant. Since the original graph crosses the y axis at -5,I am going to try using (+6). Now I need to move the blue graph up into the third quadrant.My guess would be that the (-4) should be changed to a positive number andthe graph will move up. If (x-4) moved the graph 4 unitsto the right, maybe (x+4) will move the original graph 4 units to the left. Now I need to try to move the graph into the second quadrant, which isthe top left hand corner of the graph. I haven't quitefigured out why it moved to the right 4 units. I replaced each x by (x-4).īy replacing the x with (x-4), the graph was moved 4 units to the right.It did not change it's shape or move in any other direction. The first thing I did with this problem was to graph the original equation.Īt this point I couldn't tell you exactly what had just happened, butwhen I applied "i" to this graph, it began to make a little moresense. Any of thesegraphing problems are excellent reviews for me. I didn't like graphing much when I was in school many years ago, thereforeI didn't pay much attention when this topic was discussed. Change the equation to produce a graph concave down that sharesthe same vertex. Change the equation to move the graph into the second quadrant.
Overlay a new graph replacing each x by (x-4).
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